21.6x^2+21.6x^2=1

Solution for 21.6x^2+21.6x^2=1 equation:

21.6x^2+21.6x^2=1

We move all terms to the left:

21.6x^2+21.6x^2-(1)=0

We add all the numbers together, and all the variables

43.2x^2-1=0

a = 43.2; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·43.2·(-1)
Δ = 172.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{172.8}}{2*43.2}=\frac{0-\sqrt{172.8}}{86.4}
=-\frac{\sqrt{}}{86.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{172.8}}{2*43.2}=\frac{0+\sqrt{172.8}}{86.4}
=\frac{\sqrt{}}{86.4}
$